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 1 Answer(s)

  • @gaurav.singh
    Recommendations Offline Message

    over 9 years ago

    Hi Shikha,
          You can use the following query

    select distinct concat(table_name, '.', column_name) as 'foreign key', concat(referenced_table_name, '.', referenced_column_name) as 'references' from information_schema.key_column_usage where referenced_table_name ="your_reference_table_name";

    Hope it solves your problem. Thanks

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