Join the social network of Tech Nerds, increase skill rank, get work, manage projects...
 
  • Does unifiedContacts(matching:keysToFetch:) return only unified contacts and leave out non-unified contacts?

    • 0
    • 0
    • 0
    • 0
    • 0
    • 0
    • 0
    • 5.54k
    Answer it

    When I use the Contacts Framework with Swift for iOS 15 using Xcode 13, when I use CNContactStore instance method unifiedContacts(matching:keysToFetch:), what happens to those CNContact objects that are not linked with any other CNContact objects, would they be returned as non-unified contacts, or would they be left out since they are non-unified contacts?
    The sample iOS Swift project ManagingContacts, uses both enumerateContacts(with:usingBlock:) and unifiedContacts(withIdentifier:keysToFetch:). Understanding why they choose to use each when they do may help answer the question.

    The name "unifiedContacts" suggests it only fetches unified contacts, and does not fetch non-unified contacts that otherwise would meet the specified criteria, but it doesn't make sense to me why there would ever be a need for it or why it is used in the said project when it is used.

    From my test code, it looks like they both do the same thing. What do you think about this?

    I tried this code in a test project:

    class ViewController: UIViewController {
    
        let store = CNContactStore()
        
        let keys = [CNContactGivenNameKey as CNKeyDescriptor]
        
        override func viewDidLoad() {
            super.viewDidLoad()
            // Do any additional setup after loading the view.
            
            store.requestAccess(for: .contacts) {
                
                permissionGranted, error in
                
                let request = CNContactFetchRequest(keysToFetch: self.keys)
                
                print("enumerate contacts")
                
                do {
                    
                    try self.store.enumerateContacts(with: request) {
                        
                        contact, pointer in
                        
                        print(contact.givenName)
                        
                    }
                
                } catch {
                    
                    print("error")
                    print(error.localizedDescription)
                    
                }
                
                print("unified contacts")
                
                do {
                    
                    let containers = try self.store.containers(matching: nil)
                
                    if containers.count > 1 {
                        fatalError("More than one container!")
                    }
                    
                    let predicate = CNContact.predicateForContactsInContainer(withIdentifier: self.store.defaultContainerIdentifier())
                    
                    let contacts = try self.store.unifiedContacts(matching: predicate, keysToFetch: self.keys)
    
                    for contact in contacts {
                        
                        print(contact.givenName)
                        
                    }
                    
                } catch {
                    
                    print("error")
                    print(error.localizedDescription)
    
                }
                            
            }
            
        }
    
    
    }
    


    Here's the result in the debug window:

        enumerate contacts
        Kate
        Daniel
        John
        Anna
        Hank
        David
        unified contacts
        Kate
        Daniel
        John
        Anna
        Hank
        David

     

 0 Answer(s)

Sign In
                           OR                           
                           OR                           
Register

Sign up using

                           OR                           
Forgot Password
Fill out the form below and instructions to reset your password will be emailed to you:
Reset Password
Fill out the form below and reset your password: